From 2163d7b5f44787375e3a0843763bee466f537fa4 Mon Sep 17 00:00:00 2001
From: Elegy233 <82034747+wan0ge@users.noreply.github.com>
Date: Tue, 14 Jul 2026 22:26:56 +0800
Subject: [PATCH] =?UTF-8?q?fix(merge):=20=E9=9B=B6=E5=81=8F=E7=A7=BB?=
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ZERO_DIFF_BONUS 原需 >3 对零差才能触发 100 分奖励，
导致单集断层场景仅 E1 一对零差无法拿到加成，
被无断层惩罚的批量偏移对以数量优势压制，选错偏移方向。

任意零差对集出现即表明集号一致，门槛降为 >0。
---
 danmu_api/utils/merge-util.js | 6 ++----
 1 file changed, 2 insertions(+), 4 deletions(-)

diff --git a/danmu_api/utils/merge-util.js b/danmu_api/utils/merge-util.js
index a79467b..10b3cc1 100644
--- a/danmu_api/utils/merge-util.js
+++ b/danmu_api/utils/merge-util.js
@@ -1420,13 +1420,11 @@ function findBestAlignmentOffset(
             }
             // 匹配数量规模奖励（对齐对越多越可信）
             finalScore += Math.min(matchCount * 0.15, 1.5);
-            // 零偏移奖励：偏移为 0 说明主副源集数完全对齐，是最理想情况
+            // 零偏移奖励：主副源出现任意零差对集即表明集号一致，给予强信号
             const zeroDiffCount = numericDiffs.get('0.0000') || 0;
-            if (zeroDiffCount > 3) {
+            if (zeroDiffCount > 0) {
                 finalScore += MergeWeights.EP_ALIGN.ZERO_DIFF_BONUS_BASE;
                 finalScore += zeroDiffCount * MergeWeights.EP_ALIGN.ZERO_DIFF_BONUS_PER_HIT;
-            } else if (zeroDiffCount > 0) {
-                finalScore += zeroDiffCount * 2.0;
             }
             if (finalScore > maxScore) { maxScore = finalScore; bestOffset = offset; }
         }